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(-2)平方-丨-7丨+3-2*(-1/2) 3/2*[3*(-2/3)平方-1]...

#includeint main(){double y; int i,n; double s=0,t=1; printf("要求几项的和:"); scanf("%d",&n); for(i=1;i

观察:2*4,3*5……,整个式子中只有它在变,设它为(n-1)*(n+1),因为这样的话,第一项取3,第二项取4…… 通分:得到每一项的通式(n^2-1-3)/(n^2-1)=(n+2)(n-2)/(n+1)(n-1) 【3

[-2/3+(-3/5)]➗[1+(-2/3)*(-3/5)] =(-10/15-9/15)÷(1+2/5) =(-19/15)×(5/7) =-19/21

-2*(-1/2)的平方+|-(-2)|的三次方-(-1/2) -1的六次方-(0.5-2/3)÷1/3+[-2-(-3)³]-(-1/2)3/4[4/3(1/2x-1/4)-8]=3/2x+1[(0.2-x)/(0.3)]-1={(0.1+x)/(0.2)}-2*(-1/2)的平方+|-(-2)|的三次方-(-1/2) -1的六次方-(0.5-2/3)÷1/3+[-2-(-3...

1-8+1-3=-9

3/2*5/7-(-5/7)*5/2+(-1/2)*7/5 =5/7×﹙3/2+5/2-1/2﹚ =5/7×7/2 =5/2

1又2/3-{5又3/4-2的平方/[(-1/2)的平方+3*(-3/4)]*1/8} =5/3-23/4+4/(1/4-9/4)*1/8 =5/3-23/4-1/4 =5/3-6 =-13/3

=[(-3/2)*(-0.6)]²-1÷(-8/27)+[(-0.8)*(-3/2)]²*(-3/2) =0.81+27/8-2.16 =2.025

-72.5 没明白意图,x,y,a初值多少呢? 如果a初值为12,那么a最后为0

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