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(51/4一7/8 一7/12)÷(一|又3/4

(5又1/4-7/8-7/12)÷1又3/4 =(21/4-7/8-7/12)÷7/4 =(21/4-7/8-7/12)×4/7 =21/4×4/7-7/8×4/7-7/12×4/7 =3-1/2-1/3 =3-3/6-2/6 =2又6分之1

51又3分之2÷3分之5+71又4分之3÷4分之7+91又5分之4÷5分之9 =3分之(3×51+2)×5分之3+4分之(4×71+3)×7分之4+5分之(5×91+4)×9分之5 =3分之155×5分之3+4分之287×7分之4+5分之459×9分之5 =31+41+51 =123

数学题简便计算 51又2/3÷1又2/3+71又3/4÷1又3/4 =(50+5/3)×3/5+(70+7/4)×4/7 =50×3/5+5/3×3/5+70×4/7+7/4×4/7 =30+1+40+1 =72

31又1/2*2/3+41又1/3*3/4+51又1/4*4/5+61又1/5*5/6+71又1/6*6/7 =(30 + 3/2)*2/3+(40+4/3)*3/4+(50+ 5/4)*4/5+(60+6/5)*5/6+(70+7/6)*6/7 =20+1+30+1+40+1+50+1+60+1 =20+30+50+40+60+5 =205

|-51/2|x(1/3-1/2)x3/11÷ (1-1/4) =51/2×(-1/6)×3/11÷3/4 =-17/4×3/11×4/3 =-17/11

51又2/3÷5/3+71又3/4÷7/4+91又4/5÷9/5=51又2/3×3/5+71又3/4×4/7+91又4/5×5/9 =51×3/5+2/3×3/5+71×4/7+3/4×4/7+91×5/9+4/5×5/9 =153/5+2/5+284/7+3/7+455/9+4/9 =155/5+287/7+459/9 =31+41+51 =123

81/10 规律 3/2= 9/6 分子 3的n次方-1 分母 2n

31+41+51=123

戳- -~~麻烦你出题目说清楚点~~...81又1/7...你给个空格干嘛... 81又1/7=568/7 71又1/6=427/6 61又1/5=306/5 51又1/4=205/4 41又1/3=124/3 先化完变成 568/7 * 7/8 +427/6 * 6/7+306/5 * 5/6+205/4 * 4/5+124/3 * 3/4 =568/8+427/7+306/6+205/5+...

1/6*6/7+61 =61+1/7 以此类推

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