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设a=(2,5,1,)b=(1,6,5,)则a∪b=

aUb={1,2,5,6}

集合A={1,2,3},B={2,3,4},A∪B={1,2,3,4},又全集U={1,2,3,4,5,6},所以? U (A∪B)={5,6}故答案为:{5,6}

∵A={1,2,5,6},B={0,1},∴A∪B={0,1,2,5,6}.故选A

∵A={1,3,5,6,7}B={2,3,4,5},∴A∪B={1,2,3,4,5,6,7}.故选A

解析:∵A={1,3,5},B={2,5,6},∴A∪B={1,2,3,4,5,6}又U={1,2,3,4,5,6},∴CU(A∪B)={4},故选D

∵U={1,2,3,4,5,6,7,8},A={1,3,5,7},B={2,4,5}∴A∪B={1,2,3,4,5,7},∴C u (A∪B)={6,8}故选A

∵A={1,3,4,5,B═{5,6},则∴A∪B={1,3,4,5,6}U={1,2,3,4,5,6},?U(A∪B)={2}.故选D

∵全集U={1,2,3,4,5,6,7},A={4,5,7},B={3,4},∴A∪B={3,4,5,7},则?U(A∪B)={1,2,6}.故答案为:{1,2,6}.

解析:∵A={1,3,5},B={2,5,6},∴A∪B={1,2,3,4,5,6}又U={1,2,3,4,5,6},∴C U (A∪B)={4},故选D

∵集合U={1,2,3,4,5,6},A={2,4,5},B={1,3,4,5},则(? U A)={1,3,6},(? U B)={2,6},∴(? U A)∪(? U B)={1,2,3,6},故选 A.

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